Here's something that surprised me:
a = None def f(): b = a return b def g(): b = a a = 'foo' return b
f() is perfectly fine,
g() raises an
UnboundLocalError. This is because Python optimises access to local variables using the LOAD_FAST/STORE_FAST opcode, you can easily see why this is looking at the code objects of those functions:
>>> f.__code__ .co_names () >>> f.__code__ .co_varnames ('a', 'b') >>> g.__code__ .co_names ('a',) >>> g.__code__ .co_varnames ('b',)
I actually found out this difference thanks to finally watching the Optimizations And Micro-Optimizations In CPython talk by Larry Hastings from PyCon 2010. I never realised that you could create a situation where the nonlocal scope would not be looked in.